| Chap | Page | Reference | Description | Name | Timestamp | Book |
| 1 | 9 | Concept Connnection 1.2 | Grammar error. "...a small square represent AN (not at) atom..." | Lutz | 9/4/2012 9:27:18 PM | Text |
| 2 | A-16 | 75 | Answer given in the appendix for problem 75 should be 13 cubic inches not 21 cubic inches. | Lutz | 9/4/2012 9:40:44 PM | Text |
| 3 | A-43 | For More Practice 3.22 | The answer shows lead(II) chloride in the balanced chemical equation. It should have lead(II) nitrate as the starting material. | Lutz | 11/7/2012 3:10:18 PM | Text |
| 4 | 163 | 49b | There is either an error in this problem or in the solubility table on p. 141. The solubility table on p. 141 indicates MgS is insoluble. This problem makes it appear that MgS is soluble. In reality, MgS decomposes when placed into water. | Lund | 10/10/2013 12:09:29 PM | Text |
| 5 | 174 | below equation [5.2] | "...where P1 and V1 are the initial pressure and volume of the gas and P1 and V2 are the final pressure and volume..." should be changed to "...where P1 and V1 are the initial pressure and volume of the gas and P2 and V2 are the final pressure and volume..." | Lutz | 11/7/2012 3:21:28 PM | Text |
| 6 | 239 | Table 6.5 | Standard Enthalpy of Formation for H2O (l) incorrect. Should be -285.8 kJ, NOT 2285.8 kJ | Lund | 4/12/2013 11:25:55 AM | Text |
| 6 | 245 and A20 | Problem 3 | The answer in the appendix is writen in scientific notation but does not include a decimal point. | Lutz | 12/20/2013 1:07:13 PM | Text |
| 6 | A-20 | 23 | Change in energy is listed in J when it should be in kJ. | Lutz | 12/10/2012 12:51:49 PM | Text |
| 6 | A-43 | For more Practice 6.6 | Choice (c) correctly states that burning gasoline is exothermic, but the sign for the enthalpy change should be negative for an exothermic reaction. | Lutz | 11/7/2012 3:02:59 PM | Text |
| 7 | 119 | 7.15 | Calculation uses wrong velocity for the electron and miss-converts from meters to nm. | Lutz | 11/29/2014 1:55:40 PM | Solutions Manual |
| 7 | A-44 | For Practice 7.6 (b) | In the answer key the "l" value is given as -1. "l" cannot be negative. | Lutz | 12/10/2012 12:55:18 PM | Text |
| 9 | 333 | Halfway down page | The book shows bonding in chlorine gas using two dots or a line. However, when they convert to a line they do not remove the two dots so it appears they are sharing 4 electrons. | Lutz | 12/12/2012 8:49:37 PM | Text |
| 10 | 389 | Table 10.3 | Tetrahedral geometries require sp3 hybridized orbitals | Lutz | 12/22/2012 9:38:43 AM | Text |
| 16 | 663 | Answer 16.1 Conceptual Connection | The explanation is unclear (although correct). d is the only buffer solution. a and c are eliminated due to not having conjugates. b is not a buffer because HNO3 is a strong acid. | Lutz | 4/1/2013 9:53:35 AM | Text |