ENGR 2219 - Linear Circuits I

Homework Answers

 

Note:  This is for the 10th Edition of the textbook 

 

Homework 1

2.2)  Pdev = 300 W

2.10) Pdev = Pabs = 210 W

2.17) v0 = 25 V, Pdev = Pabs = 0.575 W

2.22)  i1 = 2.0 A, P4Ω = 100 W, P50Ω = 50 W, P65Ω = 260 W, P10Ω = 90 W, P25Ω = 400 W, Pdev = Pdev = 900 W

 

Homework 2

3.16) 80 W

3.62) 72.576 W

 

Homework 3

4.12) v1 = 100 V, v2 = 20 V 

4.19) Pdev = Pabs = 40 W

4.27) i1 = -10 mA, i2 = 40 mA, i3 = -70 mA, Pdev = Pabs = 6.5 W

4.36) Pdev = Pabs =2748 W

4.46)  Pdev = Pabs = 2400 W

4.61) 20 mA

4.64) vTh = 60 V, RTh = 10 Ω

 

Homework 4

(a) I = 6 mA, V = 0

(b) I = 0, V = 0

(c) I = 3.33 mA, V = 3.33 V

(d) I = 0, V = 6.67 V

(e) I = 16.67 mA, V = 20 V

 

Homework 5

Handout 1

(1) IC = 1.93 mA, VCE = 10.35 V

(2) IC = 9.9 mA, VCE = -0.2 V

(3) IC = 0 mA, VCE = 10 V

(4) (a) IC = 3.1 mA, VCE = 0.2 V (b) IC = 3.61 mA, VCE = 1.84 V

 

Handout 2

(1) ID = 2.82 mA, VDS = 11.54 V

(2) ID = 0.54 mA, VDS = 9.9 V

 

Homework 6

5.3)

(a) -12 V 

(b) 4 V

(c) 14.5 V

(d) -11 V

(e) -16 V

(f) 0.25 to 4.25 V 

 

5.5)  -1 mA

 

5.12)   

(a) Summing Amplifier 

(b) -6 V

(c) -0.5 to 2 V

 

5.19)

(a) Non-inverting Amplifier 

(b) v0 = 1.8vs V

(c) -8.33 to 6.67 V

 

Homework 7

 

Homework 8

7.3)

(a) 0.5 A

(b) 2 ms

(c) i(t) = 0.5e-500t mA, v1(t) = -80e-500t  V, v2(t) = -35e-500t V

(d) 35.6%

 

7.25)

(a)  i(t) = 12e-20t mA, v1(t) = 20e-20t + 10 V, v2(t) = -10e-20t + 10 V

(b) 13.5 mJ

(c) 4.5 mJ and 13.5 mJ

 

7.35)

(a) -4 mA

(b) 1 mA

(c) 6.67 microseconds

(d)  i(t) = 1 - 5e-150,000t mA

7.51)

(a) -120 V

(b) 150 V

(c) 1 ms

(d) 6.75 mA

(e)  v(t) = 150 - 270e-1000t V

(f)  i(t) = 6.75e-1000t mA

 

Homework 9

8.1)

(a) iR(0) = 200 mA,  iL(0) = -300 mA,  iC(0) = 100 mA

(b) 25e-800tcos600t + 66.67e-800tsin600t V

(c)  -300e-800tcos600t - 191.7e-800tsin600t mA

 

8.4)

(a) -10,000 and -40,000 rad/s

(b) overdamped

(c) 3125 Ω

(d) -16,000 + j12,000 and -16,000 - j12,000 rad/s

(e) 2500 Ω

 

8.41)

(a) 10,000 Ω and 0.5H

(b) i(0) = 0, di(0)/dt = 48 A/s

(c) 4e-4000t - 4e-16,000t mA

(d) 115.52 μA

(e) 1.89 mA

(f) -8e-1000t + 32e-4000t V

 

8.42)

(a) 1250 Ω

(b) i(0+) = 6 mA, di(0+)/dt = 60 A/s

(c) vC(t) = 56,250te-5000t + 15e-5000t V

 

 

Homework 10

9.28) 16cos(2000t + 53.13°) A

 

9.29) -120cos(8000t) V

 

9.30) 1.77cos(4000t - 135°) A

 

9.34) 4.24cos(10,000t + 45°) V

 

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© 2011 Bill Saari

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