ENGR 2219 - Linear Circuits I
Homework Answers
Note: This is for the 9th Edition of the textbook
Homework 1
2.1) Pdev = 300 W
2.7) The interconnection is invalid
2.8) Pdev = Pabs = 210 W
2.18) i1 = 1.2 A, i2 = 0.3 A, v0 = 120 V, Pdev = Pabs = 180 W
2.22) i1 = 2.0 A, P4Ω = 100 W, P50Ω = 50 W, P65Ω = 260 W, P10Ω = 90 W, P25Ω = 400 W, Pdev = Pdev = 900 W
Homework 2
3.5) (a) 20 Ω, (b) 15 kΩ
3.10) 80 W
3.29) (a) 20 A, (b) 1080 W
Homework 3
4.6) v1 = 100 V, v2 = 20 V
4.17) Pdev = Pabs = 8800 W
4.22) i1 = -10 mA, i2 = 40 mA, i3 = -70 mA, Pdev = Pabs = 6.5 W
4.34) Pdev = Pabs = 17,940 W
4.45) Pdev = Pabs = 2400 W
4.59) (a) 20 mA
4.63) vTh = 60 V, RTh = 10 Ω
Homework 4
(a) I = 6 mA, V = 0
(b) I = 0, V = 0
(c) I = 3.33 mA, V = 3.33 V
(d) I = 0, V = 6.67 V
(e) I = 16.67 mA, V = 20 V
Homework 5
Handout 1
(1) IC = 1.93 mA, VCE = 10.35 V
(2) IC = 9.9 mA, VCE = -0.2 V
(3) IC = 0 mA, VCE = 10 V
(4) (a) IC = 3.1 mA, VCE = 0.2 V (b) IC = 3.61 mA, VCE = 1.84 V
Handout 2
(1) ID = 2.82 mA, VDS = 11.54 V
(2) ID = 0.54 mA, VDS = 9.9 V
Homework 6
5.2) -1 mA
5.3)
(a) -15 V
(b) -10 V
(c) -4 V
(d) 7 V
(e) 15 V
(f) -1.08 to 4.92 V
5.12)
(a) Summing Amplifier
(b) -6 V
(c) -0.5 to 2 V
5.17)
(a) Non-inverting Amplifier
(b) v0 = 2vs V
(c) -6 to 4 V
5.26) 20 kΩ
Homework 7
6.1)
0 < t < 2: iL(t) = -0.3e-4t + 1.3 A
t > 2: iL(t) = -0.3e-4(t-2) A
6.2)
(a) 900e-10t(1-10t) µV
(b) -59.34 µW
(c) delivering
(d) 487.21 mA
(e) 10.96 µJ
6.16)
(a) -50 x 104t +15 V
(b) 106t V
(c) 1.6 x 106t - 12 V
(d) 52 V
6.17)
0 < t < 0.5: 1.2t mA
(b) 0.5< t < 1: 1.2(t - 1) mA
Homework 8
7.4)
(a) 5 mA and 15 mA
(b) 5 mA and -5 mA
(c) 5e-20,000t mA
(d) -5e-20,000t mA
7.23)
(a) i(t) = 1.6e-50t mA, v1(t) = 32e-50t + 8 V, v2(t) = -8e-50t + 8 V
(b) 800 μJ
(c) energy trapped = 160 μJ, energy dissipated = 640 μJ
7.36)
(a) -5 mA
(b) 0.33 mA
(c) 5 x 10-6 s
(d) 0.33 - 5.33e-200,000t mA
7.55)
(a) 50 V
(b) -24 V
(c) 0.1 x 10-6 s
(d) -18.5 A
(e) -24 + 74e-10,000,000t V
(f) -18.5e-10,000,000t A
Homework 9
8.1)
(a) -10,000 and -40,000 rad/s
(b) overdamped
(c) 3125 Ω
(d) -16,000 + j12,000 and -16,000 - j12,000 rad/s
(e) 2500 Ω
8.3)
(a) iR(0+) = 48 mA, iL(0+) = -45 mA, iC(0+) = -3 mA
(b) 15e-8000tcos6000t + 17.5e-8000tsin6000t V
8.39)
(a) 10,000 Ω and 0.5H
(b) i(0) = 0, di(0)/dt = 48 A/s
(c) 4e-4000t - 4e-16,000t mA
(d) 115.52 μA
(e) 1.89 mA
(f) -8e-1000t + 32e-4000t V
8.44)
(a) 1250 Ω
(b) i(0+) = 6 mA, di(0+)/dt = 60 A/s
(c) vC(t) = 56,250te-5000t + 15e-5000t V
Homework 10
9.15)
(c) 8.32 cos(8000t + 76.31°) A
9.29)
42.43cos(50,000t + 45°) V
9.32)
42.43cos(2000t + 45°) V
9.44)
(a) 350 V
(b) 100 + j100 Ω
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